What is expand (2+x)^{0.5}(1-x)^{-0.5} ?

The solution to expand (2+x)^{0.5}(1-x)^{-0.5} is ((x+2)^{1/2})/((-x+1)^{0.5)}

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expand (2+x)^{0.5}(1-x)^{-0.5}

expand

(2 + x)^{0.5} (1 - x)^{- 0.5}

\frac{( x + 2 ) ^{\frac{1}{2}}}{( - x + 1 ) ^{0.5}}

Solution steps

(2 + x)^{0.5} (1 - x)^{- 0.5}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{( - x + 1 ) ^{0.5}} (x + 2)^{0.5}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( 2 + x ) ^{\frac{1}{2}}}{( 1 - x ) ^{0.5}}

Multiply:

1 \cdot (2 + x)^{\frac{1}{2}} = (2 + x)^{\frac{1}{2}}

= \frac{( 2 + x ) ^{\frac{1}{2}}}{( 1 - x ) ^{0.5}}

e^{- C}

1.0009 \cdot 1 0^{- 3}

What is expand (2+x)^{0.5}(1-x)^{-0.5} ?
The solution to expand (2+x)^{0.5}(1-x)^{-0.5} is ((x+2)^{1/2})/((-x+1)^{0.5)}