What is (5x10^3dkm)x(3x10^{-4}dkm) ?

The solution to (5x10^3dkm)x(3x10^{-4}dkm) is (3x^3m^2dk^2)/2

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simplify (5x10^3dkm)x(3x10^{-4}dkm)

simplify

(5 x 1 0^{3} d km) x (3 x 1 0^{- 4} d km)

\frac{3 x ^{3} m ^{2} d k ^{2}}{2}

Solution steps

(5 x \cdot 1 0^{3} d km) x (3 x \cdot 1 0^{- 4} d km)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

1 0^{3} \cdot 1 0^{- 4} = 1 0^{3 - 4}

= 5 x d km x \cdot 3 x \cdot 1 0^{3 - 4} d km

Subtract the numbers:

3 - 4 = - 1

= 5 x d km x \cdot 3 x \cdot 1 0^{- 1} d km

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

d k d k = d k^{1 + 1}

= 5 x m x \cdot 3 x \cdot 1 0^{- 1} d k^{1 + 1} m

Add the numbers:

1 + 1 = 2

= 5 x m x \cdot 3 x \cdot 1 0^{- 1} d k^{2} m

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

xxx = x^{1 + 1 + 1}

= 5 m \cdot 3 x^{1 + 1 + 1} \cdot 1 0^{- 1} d k^{2} m

Add the numbers:

1 + 1 + 1 = 3

= 5 m \cdot 3 x^{3} \cdot 1 0^{- 1} d k^{2} m

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

mm = m^{1 + 1}

= 5 \cdot 3 x^{3} \cdot 1 0^{- 1} d k^{2} m^{1 + 1}

Add the numbers:

1 + 1 = 2

= 5 \cdot 3 x^{3} \cdot 1 0^{- 1} d k^{2} m^{2}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

1 0^{- 1} = \frac{1}{10}

= 5 \cdot 3 \cdot \frac{1}{10} x^{3} m^{2} d k^{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 5 \cdot 3 x ^{3} d k ^{2} m ^{2}}{10}

Multiply the numbers:

1 \cdot 5 \cdot 3 = 15

= \frac{15 x ^{3} m ^{2} d k ^{2}}{10}

Cancel the common factor:

5

= \frac{3 x ^{3} m ^{2} d k ^{2}}{2}

- \frac{2}{14}

\frac{1}{2} (2.5 \cdot 1 0^{- 7})

3.7 \cdot 4^{- 0.2 \cdot x}

t e^{- t} cos (3 t)

2.23 \cdot 1 0^{- 16} \cdot 9.8049

What is (5x10^3dkm)x(3x10^{-4}dkm) ?
The solution to (5x10^3dkm)x(3x10^{-4}dkm) is (3x^3m^2dk^2)/2