What is ln(x^2+1)x^3ln(x^2+1) ?

The solution to ln(x^2+1)x^3ln(x^2+1) is x^3ln^2(x^2+1)

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simplify ln(x^2+1)x^3ln(x^2+1)

simplify

ln (x^{2} + 1) x^{3} ln (x^{2} + 1)

x^{3} ln^{2} (x^{2} + 1)

Solution steps

ln (x^{2} + 1) x^{3} ln (x^{2} + 1)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

ln (x^{2} + 1) ln (x^{2} + 1) = ln^{1 + 1} (x^{2} + 1)

= x^{3} ln^{1 + 1} (x^{2} + 1)

Add the numbers:

1 + 1 = 2

= x^{3} ln^{2} (x^{2} + 1)

3 e^{- j (\frac{π}{4})}

1.5 \cdot 4 \cdot 1 0^{- 4}

- 4 (2.03)^{3} (0.9)^{- 5}

What is ln(x^2+1)x^3ln(x^2+1) ?
The solution to ln(x^2+1)x^3ln(x^2+1) is x^3ln^2(x^2+1)