What is e^{-3x}(acos(5x)-bsin(5x)) ?

The solution to e^{-3x}(acos(5x)-bsin(5x)) is (acos(5x)-bsin(5x))/(e^{3x)}

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simplify e^{-3x}(acos(5x)-bsin(5x))

simplify

e^{- 3 x} (a cos (5 x) - b sin (5 x))

\frac{a cos ( 5 x ) - b sin ( 5 x )}{e ^{3 x}}

Solution steps

e^{- 3 x} (a cos (5 x) - b sin (5 x))

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{3 x}} (a cos (5 x) - b sin (5 x))

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( a cos ( 5 x ) - b sin ( 5 x ) )}{e ^{3 x}}

1 \cdot (a cos (5 x) - b sin (5 x)) = a cos (5 x) - b sin (5 x)

= \frac{a cos ( 5 x ) - b sin ( 5 x )}{e ^{3 x}}

(1.37625 \cdot 1 0^{- 8}) (0.03)

5.5 x 1 0^{- 7}

π \cdot 2^{2} c m \cdot 15 c m

(- 2)^{- 2.4}

e^{- t} s t e p [t - 1]

What is e^{-3x}(acos(5x)-bsin(5x)) ?
The solution to e^{-3x}(acos(5x)-bsin(5x)) is (acos(5x)-bsin(5x))/(e^{3x)}