What is expand (x+1)^{-1}(2(x+4)^{-1}) ?

The solution to expand (x+1)^{-1}(2(x+4)^{-1}) is 2/((x+1)(x+4))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x+1)^{-1}(2(x+4)^{-1})

expand

(x + 1)^{- 1} (2 (x + 4)^{- 1})

\frac{2}{( x + 1 ) ( x + 4 )}

Solution steps

(x + 1)^{- 1} (2 (x + 4)^{- 1})

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= 2 \cdot \frac{1}{( x + 1 )} (x + 4)^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= 2 \cdot \frac{1}{( x + 1 )} \cdot \frac{1}{( x + 4 )}

Multiply fractions:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{1 \cdot 1 \cdot 2}{( x + 1 ) ( x + 4 )}

Multiply the numbers:

1 \cdot 1 \cdot 2 = 2

= \frac{2}{( x + 1 ) ( x + 4 )}

(6.82 \cdot 1 0^{- 3}) 150

8.07 \cdot 1 0^{- 8}

e^{- 2.42 \cdot 1 0^{20}}

150 (0.02563 \cdot 1 0^{- 3})

e^{- 1584}

What is expand (x+1)^{-1}(2(x+4)^{-1}) ?
The solution to expand (x+1)^{-1}(2(x+4)^{-1}) is 2/((x+1)(x+4))