What is (mx^2-my^2)/(2m+8)*(3m+12)/(my+mx) ?

The solution to (mx^2-my^2)/(2m+8)*(3m+12)/(my+mx) is (3(x-y))/2

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simplify (mx^2-my^2)/(2m+8)*(3m+12)/(my+mx)

simplify

\frac{m x ^{2} - m y ^{2}}{2 m + 8} \cdot \frac{3 m + 12}{m y + m x}

\frac{3 ( x - y )}{2}

Solution steps

\frac{m x ^{2} - m y ^{2}}{2 m + 8} \cdot \frac{3 m + 12}{m y + m x}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( m x ^{2} - m y ^{2} ) ( 3 m + 12 )}{( 2 m + 8 ) ( m y + m x )}

Factor

m x^{2} - m y^{2} : m (x + y) (x - y)

= \frac{m ( x + y ) ( x - y ) ( 3 m + 12 )}{( 2 m + 8 ) ( m y + m x )}

Factor out common term

m

= \frac{m ( x + y ) ( x - y ) ( 3 m + 12 )}{( 2 m + 8 ) m ( y + x )}

Cancel the common factor:

m

= \frac{( x + y ) ( x - y ) ( 3 m + 12 )}{( 2 m + 8 ) ( y + x )}

Apply the commutative law:

y + x = x + y

= \frac{( x + y ) ( x - y ) ( 3 m + 12 )}{( 2 m + 8 ) ( x + y )}

Cancel the common factor:

x + y

= \frac{( x - y ) ( 3 m + 12 )}{2 m + 8}

Factor

3 m + 12 : 3 (m + 4)

= \frac{( x - y ) \cdot 3 ( m + 4 )}{2 m + 8}

Factor

2 m + 8 : 2 (m + 4)

= \frac{( x - y ) \cdot 3 ( m + 4 )}{2 ( m + 4 )}

Cancel the common factor:

m + 4

= \frac{( x - y ) \cdot 3}{2}

= \frac{3 ( x - y )}{2}

x^{2} - 8 x \leq - 12

lo g_{2} (3)

3 x - 6 = 4 (2 - 3 x) - 8 x

x^{2} + 8 x + 22 = 19 x + 4

\frac{1}{3} - \frac{1}{12}

What is (mx^2-my^2)/(2m+8)*(3m+12)/(my+mx) ?
The solution to (mx^2-my^2)/(2m+8)*(3m+12)/(my+mx) is (3(x-y))/2