What are the solutions to the equation 3x^2+1=34 ?

The solutions to the equation 3x^2+1=34 are x=sqrt(11),x=-sqrt(11)

Find the zeros of 3x^2+1=34

The zeros of 3x^2+1=34 are x=sqrt(11),x=-sqrt(11)

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3 x^{2} + 1 = 34

x = 11, x = - 11

Decimal Notation

x = 3.31662 \dots, x = - 3.31662 \dots

Solution steps

3 x^{2} + 1 = 34

Move

1

to the right side

3 x^{2} = 33

Divide both sides by

3

x^{2} = 11

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 11, x = - 11

(x - 9)^{2} = - 7

\frac{r}{2} \geq 2

a^{3}

\frac{x}{x + 7} > 0

\frac{2}{3} (6 x + 3) = 4 x + 2

What are the solutions to the equation 3x^2+1=34 ?
The solutions to the equation 3x^2+1=34 are x=sqrt(11),x=-sqrt(11)
Find the zeros of 3x^2+1=34
The zeros of 3x^2+1=34 are x=sqrt(11),x=-sqrt(11)