What is e^{-10}ln(1+e^{-10}) ?

The solution to e^{-10}ln(1+e^{-10}) is 1/(e^{10)}ln(1/(e^{10)}+1)

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simplify e^{-10}ln(1+e^{-10})

simplify

e^{- 10} ln (1 + e^{- 10})

\frac{1}{e ^{10}} ln (\frac{1}{e ^{10}} + 1)

Decimal Notation

2.06111 E - 9

Solution steps

e^{- 10} ln (1 + e^{- 10})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{10}} ln (e^{- 10} + 1)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{10}} ln (\frac{1}{e ^{10}} + 1)

\frac{x ^{0}}{x ^{15}} 0

e^{u} \cdot e^{- u}

(4.8 \cdot 1 0^{- 19}) (600)

3 (2.03)^{2} (0.9)^{- 4} (0.03)

e^{- 0.54539}

What is e^{-10}ln(1+e^{-10}) ?
The solution to e^{-10}ln(1+e^{-10}) is 1/(e^{10)}ln(1/(e^{10)}+1)