What is the answer to 0=12^2+4x-5 ?

The answer to 0=12^2+4x-5 is x=-139/4

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0=12^2+4x-5

0 = 1 2^{2} + 4 x - 5

x = - \frac{139}{4}

Decimal Notation

x = - 34.75

Solution steps

0 = 1 2^{2} + 4 x - 5

Switch sides

1 2^{2} + 4 x - 5 = 0

1 2^{2} = 144

144 + 4 x - 5 = 0

Group like terms

4 x + 144 - 5 = 0

Add/Subtract the numbers:

144 - 5 = 139

4 x + 139 = 0

Move

139

to the right side

4 x = - 139

Divide both sides by

4

x = - \frac{139}{4}

(32 x^{- 40} y^{- 35})^{- \frac{3}{5}}

\frac{2 π}{3} + \frac{π}{3}

2 + 4 g < 10

\frac{3 x}{4} - 5 = \frac{1}{4}

10 - 12 - [(- 9) + (- 1)]