What is (a-b+c)^2(a+b-c)^2 ?

The solution to (a-b+c)^2(a+b-c)^2 is (a+c-b)^2(a+b-c)^2

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simplify (a-b+c)^2(a+b-c)^2

simplify

(a - b + c)^{2} (a + b - c)^{2}

(a + c - b)^{2} (a + b - c)^{2}

Solution steps

(a - b + c)^{2} (a + b - c)^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(a + c - b)^{2} (a + b - c)^{2} = ((a + c - b) (a + b - c))^{2}

= ((a + c - b) (a + b - c))^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= (a + c - b)^{2} (a + b - c)^{2}

e^{- \frac{l n ( x )}{a}}

15 \cdot 6.94 x 1 0^{- 3}

e^{- x} ln (e) (x + 3)

(4 x^{3} y) (2 x^{4})

e^{- \frac{1}{5} (2)}

What is (a-b+c)^2(a+b-c)^2 ?
The solution to (a-b+c)^2(a+b-c)^2 is (a+c-b)^2(a+b-c)^2