What are the solutions to the equation 0=x^2-2x ?

The solutions to the equation 0=x^2-2x are x=2,x=0

Find the zeros of 0=x^2-2x

The zeros of 0=x^2-2x are x=2,x=0

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0 = x^{2} - 2 x

x = 2, x = 0

Solution steps

0 = x^{2} - 2 x

Switch sides

x^{2} - 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot 0 = 2

x_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2}{2 \cdot 1} : 2

x = \frac{- ( - 2 ) - 2}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 2, x = 0

x^{4} + 4 x^{2} - 5

x - \frac{9}{10} = 7 x + \frac{1}{2}

x^{2} + 10 x - 15 = 0

∣ 1 + 6 n ∣ < 23

∣ 2 x + 6 ∣ = ∣ x - 2 ∣

What are the solutions to the equation 0=x^2-2x ?
The solutions to the equation 0=x^2-2x are x=2,x=0
Find the zeros of 0=x^2-2x
The zeros of 0=x^2-2x are x=2,x=0