What are the solutions to the equation 3x^2+7x=0 ?

The solutions to the equation 3x^2+7x=0 are x=0,x=-7/3

Find the zeros of 3x^2+7x=0

The zeros of 3x^2+7x=0 are x=0,x=-7/3

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3 x^{2} + 7 x = 0

x = 0, x = - \frac{7}{3}

Solution steps

3 x^{2} + 7 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

7^{2} - 4 \cdot 3 \cdot 0 = 7

x_{1, 2} = \frac{- 7 \pm 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 7 + 7}{2 \cdot 3}, x_{2} = \frac{- 7 - 7}{2 \cdot 3}

x = \frac{- 7 + 7}{2 \cdot 3} : 0

x = \frac{- 7 - 7}{2 \cdot 3} : - \frac{7}{3}

The solutions to the quadratic equation are:

x = 0, x = - \frac{7}{3}

\frac{5 x ^{4} - 46 x ^{3} + 84 x ^{2} - 50 x + 7}{x - 1}

- 42 \cdot 47

5 s + 2 > 7

\frac{\frac{1}{2}}{\frac{2}{3}}

12 n - 7 - 3 n = 11

What are the solutions to the equation 3x^2+7x=0 ?
The solutions to the equation 3x^2+7x=0 are x=0,x=-7/3
Find the zeros of 3x^2+7x=0
The zeros of 3x^2+7x=0 are x=0,x=-7/3