What is [(5m-9n^2)^{-4}]^7 ?

The solution to [(5m-9n^2)^{-4}]^7 is 1/((5m-9n^2)^{28)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify [(5m-9n^2)^{-4}]^7

simplify

[(5 m - 9 n^{2})^{- 4}]^{7}

\frac{1}{( 5 m - 9 n ^{2} ) ^{28}}

Solution steps

((5 m - 9 n^{2})^{- 4})^{7}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

= (5 m - 9 n^{2})^{- 4 \cdot 7}

Multiply the numbers:

4 \cdot 7 = 28

= (5 m - 9 n^{2})^{- 28}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(5 m - 9 n^{2})^{- 28} = \frac{1}{( 5 m - 9 n ^{2} ) ^{28}}

= \frac{1}{( 5 m - 9 n ^{2} ) ^{28}}

3.8 x 1 0^{- 3}

9.4424 \cdot 1 0^{- 3} \cdot 1000

2 e^{- 3 t} \cdot e^{5 t}

3.8 x 1 0^{- 5}

What is [(5m-9n^2)^{-4}]^7 ?
The solution to [(5m-9n^2)^{-4}]^7 is 1/((5m-9n^2)^{28)}