What is sqrt(1-2x)sqrt(4-x^2) ?

The solution to sqrt(1-2x)sqrt(4-x^2) is sqrt((-2x+1)(-x^2+4))

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simplify sqrt(1-2x)sqrt(4-x^2)

simplify

1 - 2 x 4 - x^{2}

(- 2 x + 1) (- x^{2} + 4)

Solution steps

1 - 2 x 4 - x^{2}

Apply radical rule:

a b = a \cdot b,

assuming

a \geq 0, b \geq 0

- 2 x + 1 - x^{2} + 4 = (- 2 x + 1) (- x^{2} + 4)

= (- 2 x + 1) (- x^{2} + 4)

e^{9 x} \cdot e^{- x}

d x d x^{- 4}

2 (e^{- 0.04})^{1}

2 (e^{- 0.04})^{0}

e^{- \frac{17}{2} l n (x)}

What is sqrt(1-2x)sqrt(4-x^2) ?
The solution to sqrt(1-2x)sqrt(4-x^2) is sqrt((-2x+1)(-x^2+4))