What are the solutions to the equation 0=x^2-12x+33 ?

The solutions to the equation 0=x^2-12x+33 are x=6+sqrt(3),x=6-sqrt(3)

Find the zeros of 0=x^2-12x+33

The zeros of 0=x^2-12x+33 are x=6+sqrt(3),x=6-sqrt(3)

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0 = x^{2} - 12 x + 33

x = 6 + 3, x = 6 - 3

Decimal Notation

x = 7.73205 \dots, x = 4.26794 \dots

Solution steps

0 = x^{2} - 12 x + 33

Switch sides

x^{2} - 12 x + 33 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 33}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 33 = 23

x_{1, 2} = \frac{- ( - 12 ) \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 3}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2 3}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2 3}{2 \cdot 1} : 6 + 3

x = \frac{- ( - 12 ) - 2 3}{2 \cdot 1} : 6 - 3

The solutions to the quadratic equation are:

x = 6 + 3, x = 6 - 3

- 2 x^{2} + 3 x + 12 > 10

2 i - 7 i + 10

3 a + 10 = 4 a - 2

36 x^{2} - 64 = 0

(- 1)^{\frac{5}{3}}

What are the solutions to the equation 0=x^2-12x+33 ?
The solutions to the equation 0=x^2-12x+33 are x=6+sqrt(3),x=6-sqrt(3)
Find the zeros of 0=x^2-12x+33
The zeros of 0=x^2-12x+33 are x=6+sqrt(3),x=6-sqrt(3)