What is t^2e^{-3t}cos(2t) ?

The solution to t^2e^{-3t}cos(2t) is (t^2cos(2t))/(e^{3t)}

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simplify t^2e^{-3t}cos(2t)

simplify

t^{2} e^{- 3 t} cos (2 t)

\frac{t ^{2} cos ( 2 t )}{e ^{3 t}}

Solution steps

t^{2} e^{- 3 t} cos (2 t)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{3 t}} t^{2} cos (2 t)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot t ^{2} cos ( 2 t )}{e ^{3 t}}

Multiply:

1 \cdot t^{2} = t^{2}

= \frac{t ^{2} cos ( 2 t )}{e ^{3 t}}

- 14 π e^{- 1^{2}}

3.4 \cdot 1 0^{- 2} \cdot 4

(0.65 \cdot 1 0^{- 16}) (0.98)

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What is t^2e^{-3t}cos(2t) ?
The solution to t^2e^{-3t}cos(2t) is (t^2cos(2t))/(e^{3t)}