What is t^2(2cos(t)-sin(t)t)^2 ?

The solution to t^2(2cos(t)-sin(t)t)^2 is t^2(-tsin(t)+2cos(t))^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify t^2(2cos(t)-sin(t)t)^2

simplify

t^{2} (2 cos (t) - sin (t) t)^{2}

t^{2} (- t sin (t) + 2 cos (t))^{2}

Solution steps

t^{2} (2 cos (t) - sin (t) t)^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

t^{2} (- t sin (t) + 2 cos (t))^{2} = (t (- t sin (t) + 2 cos (t)))^{2}

= (t (- t sin (t) + 2 cos (t)))^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= t^{2} (- t sin (t) + 2 cos (t))^{2}

π^{2} \cdot π

x^{2} y^{2} (9 x^{2} y^{2} - 5 x + 4)

3.02 e^{3} \cdot e^{- 6}

e^{- (2 l n (x^{2} + 1))}

(4.45 x 1 0^{8}) (3.6 x 1 0^{7})

What is t^2(2cos(t)-sin(t)t)^2 ?
The solution to t^2(2cos(t)-sin(t)t)^2 is t^2(-tsin(t)+2cos(t))^2