What are the solutions to the equation 2x^2+3x+2=0 ?

The solutions to the equation 2x^2+3x+2=0 are x=-3/4+i(sqrt(7))/4 ,x=-3/4-i(sqrt(7))/4

Find the zeros of 2x^2+3x+2=0

The zeros of 2x^2+3x+2=0 are x=-3/4+i(sqrt(7))/4 ,x=-3/4-i(sqrt(7))/4

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2 x^{2} + 3 x + 2 = 0

x = - \frac{3}{4} + i \frac{7}{4}, x = - \frac{3}{4} - i \frac{7}{4}

Solution steps

2 x^{2} + 3 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

Simplify

3^{2} - 4 \cdot 2 \cdot 2 : 7 i

x_{1, 2} = \frac{- 3 \pm 7 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 7 i}{2 \cdot 2}, x_{2} = \frac{- 3 - 7 i}{2 \cdot 2}

x = \frac{- 3 + 7 i}{2 \cdot 2} : - \frac{3}{4} + i \frac{7}{4}

x = \frac{- 3 - 7 i}{2 \cdot 2} : - \frac{3}{4} - i \frac{7}{4}

The solutions to the quadratic equation are:

x = - \frac{3}{4} + i \frac{7}{4}, x = - \frac{3}{4} - i \frac{7}{4}

12 x^{2} - 31 x + 9

2 x + 15 = 2 x - 15

294 r^{2} - 150

n^{2} - 5 n - 24

\frac{3}{5} - 1

What are the solutions to the equation 2x^2+3x+2=0 ?
The solutions to the equation 2x^2+3x+2=0 are x=-3/4+i(sqrt(7))/4 ,x=-3/4-i(sqrt(7))/4
Find the zeros of 2x^2+3x+2=0
The zeros of 2x^2+3x+2=0 are x=-3/4+i(sqrt(7))/4 ,x=-3/4-i(sqrt(7))/4