What is e^{-(ln(2)+1/2)} ?

The solution to e^{-(ln(2)+1/2)} is 1/(e^{\frac{2ln(2)+1){2}}}

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simplify e^{-(ln(2)+1/2)}

simplify

e^{- (l n (2) + \frac{1}{2})}

\frac{1}{e ^{\frac{2 l n ( 2 ) + 1}{2}}}

Decimal Notation

0.30326 \dots

Solution steps

e^{- (l n (2) + \frac{1}{2})}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{(l n (2) + \frac{1}{2})}}

Remove parentheses:

(a) = a

= \frac{1}{e ^{l n (2) + \frac{1}{2}}}

e^{l n (2) + \frac{1}{2}} = e^{\frac{2 l n ( 2 ) + 1}{2}}

= \frac{1}{e ^{\frac{l n ( 2 ) \cdot 2 + 1}{2}}}

(x, 0) (3, 1)

(0^{- 2}) (0^{2})

2 x + 1 \cdot x

(85 C^{3}) 15 C^{2}

What is e^{-(ln(2)+1/2)} ?
The solution to e^{-(ln(2)+1/2)} is 1/(e^{\frac{2ln(2)+1){2}}}