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Popular >

simplify e^{-0.5ln(x^2+1)}

Solution

simplify

e^{- 0.5 l n (x^{2} + 1)}

Solution

\frac{1}{x ^{2} + 1}

Solution steps

e^{- 0.5 l n (x^{2} + 1)}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{0.5 l n (x^{2} + 1)}}

e^{0.5 l n (x^{2} + 1)} = x^{2} + 1

= \frac{1}{x ^{2} + 1}

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Frequently Asked Questions (FAQ)

What is e^{-0.5ln(x^2+1)} ?
The solution to e^{-0.5ln(x^2+1)} is 1/(sqrt(x^2+1))