simplify 9.4*2^{-1}

Solution

simplify

9.4 \cdot 2^{- 1}

\frac{47}{10}

Decimal Notation

4.7

Solution steps

9.4 \cdot 2^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

2^{- 1} = \frac{1}{2}

= 9.4 \cdot \frac{1}{2}

9.4 = \frac{47}{5}

= \frac{47}{5} \cdot \frac{1}{2}

\frac{47}{5} \cdot \frac{1}{2} = \frac{47}{10}

= \frac{47}{10}

e x p o^{- l n (1 - x)}

(- 2 e)^{(- 2 x)}

x^{2} (1 + sin^{2} (t))^{2}

- π^{2} \cdot π

168.36 \cdot (7.5 \cdot 1 0^{- 1})