What are the solutions to the equation -2(x+7)^2=-162 ?

The solutions to the equation -2(x+7)^2=-162 are x=2,x=-16

Find the zeros of -2(x+7)^2=-162

The zeros of -2(x+7)^2=-162 are x=2,x=-16

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- 2 (x + 7)^{2} = - 162

x = 2, x = - 16

Solution steps

- 2 (x + 7)^{2} = - 162

Divide both sides by

- 2

(x + 7)^{2} = 81

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 7 = 81 : x = 2

Solve

x + 7 = - 81 : x = - 16

The solutions to the quadratic equation are:

x = 2, x = - 16

\frac{1}{5} \frac{1}{5} = \frac{5}{5}

\frac{4 - 13}{3 - 7}

4 w^{2} + 12 w + 9 = 169

5^{2} \cdot 5^{4}

lo g_{3} (\frac{1}{2})

What are the solutions to the equation -2(x+7)^2=-162 ?
The solutions to the equation -2(x+7)^2=-162 are x=2,x=-16
Find the zeros of -2(x+7)^2=-162
The zeros of -2(x+7)^2=-162 are x=2,x=-16