What is (\sqrt[4]{-y})^2 ?

The solution to (\sqrt[4]{-y})^2 is isqrt(y)

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simplify (\sqrt[4]{-y})^2

simplify

i y

Solution steps

Apply radical rule:

= ((- y)^{\frac{1}{4}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= (- y)^{\frac{1}{4} \cdot 2}

\frac{1}{4} \cdot 2 = \frac{1}{2}

= (- y)^{\frac{1}{2}}

a^{\frac{1}{2}} = a

= - y

Apply radical rule:

- a = - 1 a,

assuming

a \geq 0

- y = - 1 y

= - 1 y

Apply imaginary number rule:

- 1 = i

= i y

1 \cdot (5.67 \cdot 1 0^{- 8}) 4830

(- 1.7) (4 \cdot 1 0^{- 5})

400 \cdot (1.6 \cdot 1 0^{- 19})

(a x) (a^{i} z)