What is ((i+1))/((i-1)) ?

The solution to ((i+1))/((i-1)) is -i

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simplify ((i+1))/((i-1))

simplify

\frac{( i + 1 )}{( i - 1 )}

- i

Solution steps

\frac{i + 1}{i - 1}

Rewrite

i + 1

in standard complex form:

1 + i

Rewrite

i - 1

in standard complex form:

- 1 + i

= \frac{1 + i}{- 1 + i}

Multiply by the conjugate

\frac{- 1 - i}{- 1 - i}

= \frac{( 1 + i ) ( - 1 - i )}{( - 1 + i ) ( - 1 - i )}

Simplify

\frac{( 1 + i ) ( - 1 - i )}{( - 1 + i ) ( - 1 - i )} : \frac{- 2 i}{2}

= \frac{- 2 i}{2}

Cancel the common factor:

2

= - i

\frac{f}{- 3.2} = 0.01

\frac{7}{2} \cdot \frac{3}{4}

\frac{x ^{2} + 6 x + 12}{x + 2} < 1

[\frac{7 !}{3 !} (\frac{1}{2})^{3} (1 - \frac{1}{2})^{7 - 3}] \cdot \frac{1}{2}

- 2 u + 2 = - 7 u + 17