What is ((a+b)^{-7})/((a+b)^{-9)} ?

The solution to ((a+b)^{-7})/((a+b)^{-9)} is (a+b)^2

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simplify ((a+b)^{-7})/((a+b)^{-9)}

simplify

\frac{( a + b ) ^{- 7}}{( a + b ) ^{- 9}}

(a + b)^{2}

Solution steps

\frac{( a + b ) ^{- 7}}{( a + b ) ^{- 9}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

= (a + b)^{- 7 - (- 9)}

Apply rule

- (- a) = a

= (a + b)^{- 7 + 9}

Add/Subtract the numbers:

- 7 + 9 = 2

= (a + b)^{2}

0.4 x 1 0^{- 8}

3.625 \cdot 1 0^{- 8}

(e^{12 x})^{\frac{1}{3}}

16 a^{2} b^{2}

(x^{9} y) \cdot (x^{10} y^{5})

What is ((a+b)^{-7})/((a+b)^{-9)} ?
The solution to ((a+b)^{-7})/((a+b)^{-9)} is (a+b)^2