What is e^{-rt}(at+b^1)(K) ?

The solution to e^{-rt}(at+b^1)(K) is (K(ta+b))/(e^{rt)}

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simplify e^{-rt}(at+b^1)(K)

simplify

e^{- r t} (a t + b^{1}) (K)

\frac{K ( t a + b )}{e ^{r t}}

Solution steps

e^{- r t} (a t + b^{1}) (K)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{r t}} K (t a + b^{1})

Apply rule

a^{1} = a

b^{1} = b

= \frac{1}{e ^{r t}} K (t a + b)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( a t + b ) K}{e ^{r t}}

Multiply:

1 \cdot (a t + b) = (a t + b)

= \frac{K ( t a + b )}{e ^{r t}}

\frac{( 8 ) ^{- 2}}{( e ) ^{- 2}}

(4 a^{2} b^{4}) (3 a^{4} b^{3}) 2

2.79 \cdot 1 0^{- 16} \cdot 9.8049

e^{- 0.06921} (1 - e^{0.006472})

(3 x^{2} y) (10 x^{5} y^{3})

What is e^{-rt}(at+b^1)(K) ?
The solution to e^{-rt}(at+b^1)(K) is (K(ta+b))/(e^{rt)}