What are the solutions to the equation 3(x^2+12)=84 ?

The solutions to the equation 3(x^2+12)=84 are x=4,x=-4

Find the zeros of 3(x^2+12)=84

The zeros of 3(x^2+12)=84 are x=4,x=-4

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3 (x^{2} + 12) = 84

x = 4, x = - 4

Solution steps

3 (x^{2} + 12) = 84

Divide both sides by

3

x^{2} + 12 = 28

Move

12

to the right side

x^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 16, x = - 16

16 = 4

- 16 = - 4

x = 4, x = - 4

2 x^{2} = 17 x + 9

(e^{\frac{2 x}{3}})^{2}

\frac{x - 5}{x ^{2} + 3 x} > 0

(t + 15)^{2} + 5 = 0

\frac{3}{4} (\frac{2}{5} x - \frac{4}{9}) = \frac{1}{2}

What are the solutions to the equation 3(x^2+12)=84 ?
The solutions to the equation 3(x^2+12)=84 are x=4,x=-4
Find the zeros of 3(x^2+12)=84
The zeros of 3(x^2+12)=84 are x=4,x=-4