What is (0.2)^1*Z^{-1} ?

The solution to (0.2)^1*Z^{-1} is 1/(5Z)

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simplify (0.2)^1*Z^{-1}

simplify

(0.2)^{1} \cdot Z^{- 1}

\frac{1}{5 Z}

Solution steps

0. 2^{1} Z^{- 1}

Apply exponent rule:

a^{1} = a

0. 2^{1} = 0.2

= 0.2 Z^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

Z^{- 1} = \frac{1}{Z}

= 0.2 \cdot \frac{1}{Z}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{0.2 \cdot 1}{Z}

Multiply the numbers:

0.2 \cdot 1 = 0.2

= \frac{0.2}{Z}

Simplify

\frac{0.2}{Z} : \frac{2}{10 Z}

= \frac{2}{10 Z}

Cancel the numbers:

\frac{2}{10} = \frac{1}{5}

= \frac{1}{5 Z}

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