What are the solutions to the equation 4x^2-24x+100=0 ?

The solutions to the equation 4x^2-24x+100=0 are x=3+4i,x=3-4i

Find the zeros of 4x^2-24x+100=0

The zeros of 4x^2-24x+100=0 are x=3+4i,x=3-4i

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4 x^{2} - 24 x + 100 = 0

x = 3 + 4 i, x = 3 - 4 i

Solution steps

4 x^{2} - 24 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 4 \cdot 100}{2 \cdot 4}

Simplify

(- 24)^{2} - 4 \cdot 4 \cdot 100 : 32 i

x_{1, 2} = \frac{- ( - 24 ) \pm 32 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 32 i}{2 \cdot 4}, x_{2} = \frac{- ( - 24 ) - 32 i}{2 \cdot 4}

x = \frac{- ( - 24 ) + 32 i}{2 \cdot 4} : 3 + 4 i

x = \frac{- ( - 24 ) - 32 i}{2 \cdot 4} : 3 - 4 i

The solutions to the quadratic equation are:

x = 3 + 4 i, x = 3 - 4 i

56 (1000) - 0.02 (1000)^{2}

\frac{x}{5} - \frac{2 x}{15} \geq \frac{x + 4}{3}

\frac{2}{5} x - 4 = - \frac{1}{5} x + 8

10 y^{2} - 21 y - 10

9 x - 10 = 5 x + 2 (2 x - 5)

What are the solutions to the equation 4x^2-24x+100=0 ?
The solutions to the equation 4x^2-24x+100=0 are x=3+4i,x=3-4i
Find the zeros of 4x^2-24x+100=0
The zeros of 4x^2-24x+100=0 are x=3+4i,x=3-4i