What is the d/(dt)(e^{-(s+4)t}) ?

The d/(dt)(e^{-(s+4)t}) is e^{-(s+4)t}(-s-4)

What is the first d/(dt)(e^{-(s+4)t}) ?

The first d/(dt)(e^{-(s+4)t}) is e^{-(s+4)t}(-s-4)

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\frac{d}{d t} (e^{- (s + 4) t})

e^{- (s + 4) t} (- s - 4)

Solution steps

\frac{d}{d t} (e^{- (s + 4) t})

Apply the chain rule:

e^{- (s + 4) t} \frac{d}{d t} (- (s + 4) t)

= e^{- (s + 4) t} \frac{d}{d t} (- (s + 4) t)

\frac{d}{d t} (- (s + 4) t) = - s - 4

= e^{- (s + 4) t} (- s - 4)

[(2 x + 1)^{7}]^{^{'}}

\frac{e ^{- 0.05 t}}{e ^{0.2 t}}

e^{x^{6}}

(6)^{2^{^{'}}}

What is the d/(dt)(e^{-(s+4)t}) ?
The d/(dt)(e^{-(s+4)t}) is e^{-(s+4)t}(-s-4)
What is the first d/(dt)(e^{-(s+4)t}) ?
The first d/(dt)(e^{-(s+4)t}) is e^{-(s+4)t}(-s-4)