What is K(t)(t)^{-3}K''(t) ?

The solution to K(t)(t)^{-3}K''(t) is (K(t)K''(t))/(t^3)

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simplify K(t)(t)^{-3}K''(t)

simplify

K (t) (t)^{- 3} K^{''} (t)

\frac{K ( t ) K '' ( t )}{t ^{3}}

Solution steps

K (t) (t)^{- 3} K^{''} (t)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{t ^{3}} K (t) K^{^{''}} (t)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot K ( t ) K ^{^{''}} ( t )}{t ^{3}}

Multiply:

1 \cdot K (t) = K (t)

= \frac{K ( t ) K ^{^{''}} ( t )}{t ^{3}}

((\frac{3}{4})^{3})^{4}

ln (x) x^{- 2}

e^{- 0.999}

(e^{4 x})^{3}

What is K(t)(t)^{-3}K''(t) ?
The solution to K(t)(t)^{-3}K''(t) is (K(t)K''(t))/(t^3)