What are the solutions to the equation 39^2+80^2=c^2 ?

The solutions to the equation 39^2+80^2=c^2 are c=89,c=-89

Find the zeros of 39^2+80^2=c^2

The zeros of 39^2+80^2=c^2 are c=89,c=-89

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3 9^{2} + 8 0^{2} = c^{2}

c = 89, c = - 89

Solution steps

3 9^{2} + 8 0^{2} = c^{2}

Switch sides

c^{2} = 3 9^{2} + 8 0^{2}

Simplify

3 9^{2} + 8 0^{2} : 7921

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 7921, c = - 7921

7921 = 89

- 7921 = - 89

c = 89, c = - 89

5 x^{2} - 6 x - 27 = 0

25 a^{4} - 16 b^{6}

2 x^{2} + 4 x - 96 = 0

3 (x - 1) - 4 (2 x + 3) \leq 14

h (5) = 175 (1.028)^{5}

What are the solutions to the equation 39^2+80^2=c^2 ?
The solutions to the equation 39^2+80^2=c^2 are c=89,c=-89
Find the zeros of 39^2+80^2=c^2
The zeros of 39^2+80^2=c^2 are c=89,c=-89