What is (cos(3x))(e^{-2x}(-2)) ?

The solution to (cos(3x))(e^{-2x}(-2)) is -(2cos(3x))/(e^{2x)}

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simplify (cos(3x))(e^{-2x}(-2))

simplify

(cos (3 x)) (e^{- 2 x} (- 2))

- \frac{2 cos ( 3 x )}{e ^{2 x}}

Solution steps

(cos (3 x)) (e^{- 2 x} (- 2))

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= (- 2) \frac{1}{e ^{2 x}} cos (3 x)

Remove parentheses:

(- a) = - a

= - cos (3 x) \frac{1}{e ^{2 x}} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{1 \cdot cos ( 3 x ) \cdot 2}{e ^{2 x}}

Multiply the numbers:

1 \cdot 2 = 2

= - \frac{2 cos ( 3 x )}{e ^{2 x}}

(z + 1)^{2} (z - 1)^{2}

- 3 e^{- 2 x}

3 t e^{- 2 t} cos (θ) t

(L {t}) (e^{- π s})

\frac{( y ^{2} + 1 ) ^{2}}{y ^{2}}

What is (cos(3x))(e^{-2x}(-2)) ?
The solution to (cos(3x))(e^{-2x}(-2)) is -(2cos(3x))/(e^{2x)}