What are the solutions to the equation 5(x-2)^2+20=-60 ?

The solutions to the equation 5(x-2)^2+20=-60 are x=4i+2,x=-4i+2

Find the zeros of 5(x-2)^2+20=-60

The zeros of 5(x-2)^2+20=-60 are x=4i+2,x=-4i+2

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5 (x - 2)^{2} + 20 = - 60

x = 4 i + 2, x = - 4 i + 2

Solution steps

5 (x - 2)^{2} + 20 = - 60

Move

20

to the right side

5 (x - 2)^{2} = - 80

Divide both sides by

5

(x - 2)^{2} = - 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = - 16 : x = 4 i + 2

Solve

x - 2 = - - 16 : x = - 4 i + 2

The solutions to the quadratic equation are:

x = 4 i + 2, x = - 4 i + 2

x^{2} + x - 30 \leq 0

ln (0.75)

∣ u - 1 ∣ = - \frac{1}{4}

\frac{7}{12}

(x + y + z)^{2}

What are the solutions to the equation 5(x-2)^2+20=-60 ?
The solutions to the equation 5(x-2)^2+20=-60 are x=4i+2,x=-4i+2
Find the zeros of 5(x-2)^2+20=-60
The zeros of 5(x-2)^2+20=-60 are x=4i+2,x=-4i+2