What is (x+1)^2(x-3)^2(x^2-x-2) ?

The solution to (x+1)^2(x-3)^2(x^2-x-2) is (x+1)^2(x-3)^2(x^2-x-2)

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simplify (x+1)^2(x-3)^2(x^2-x-2)

simplify

(x + 1)^{2} (x - 3)^{2} (x^{2} - x - 2)

(x + 1)^{2} (x - 3)^{2} (x^{2} - x - 2)

Solution steps

(x + 1)^{2} (x - 3)^{2} (x^{2} - x - 2)

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(x + 1)^{2} (x - 3)^{2} = ((x + 1) (x - 3))^{2}

= ((x + 1) (x - 3))^{2} (x^{2} - x - 2)

((x + 1) (x - 3))^{2} = (x + 1)^{2} (x - 3)^{2}

= (x + 1)^{2} (x - 3)^{2} (x^{2} - x - 2)

(1.04 \cdot (1 0^{- 3})) (36110)

\frac{1}{2} x π x^{9}

2 (x - 3)^{2} (x + 2)^{2}

, x^{- \frac{1}{6}}

- (x + 14)^{2} (x - 5)^{2}

What is (x+1)^2(x-3)^2(x^2-x-2) ?
The solution to (x+1)^2(x-3)^2(x^2-x-2) is (x+1)^2(x-3)^2(x^2-x-2)