What is expand (2x^{-2}y^3)^{-2} ?

The solution to expand (2x^{-2}y^3)^{-2} is (x^4)/(4y^6)

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expand (2x^{-2}y^3)^{-2}

expand

(2 x^{- 2} y^{3})^{- 2}

\frac{x ^{4}}{4 y ^{6}}

Solution steps

(2 x^{- 2} y^{3})^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{( 2 x ^{- 2} y ^{3} ) ^{2}}

(2 x^{- 2} y^{3})^{2} = \frac{2 ^{2} y ^{6}}{x ^{4}}

= \frac{1}{\frac{2 ^{2} y ^{6}}{x ^{4}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{x ^{4}}{2 ^{2} y ^{6}}

2^{2} = 4

= \frac{x ^{4}}{4 y ^{6}}

v (u v^{2}) (4 u^{2} v^{3})

\frac{e ^{- 2}}{e ^{- 4 x}}

e^{- 2 \cdot l n (10)}

- 12 e^{- 3 l n (2)}

What is expand (2x^{-2}y^3)^{-2} ?
The solution to expand (2x^{-2}y^3)^{-2} is (x^4)/(4y^6)