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Popular >

simplify e^{-ln(1-y)dy}

Solution

simplify

e^{- l n (1 - y) d y}

Solution

\frac{1}{( - y + 1 ) ^{y d}}

Solution steps

e^{- l n (1 - y) d y}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{y d l n (- y + 1)}}

e^{l n (1 - y) d y} = (1 - y)^{y d}

= \frac{1}{( 1 - y ) ^{y d}}

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Frequently Asked Questions (FAQ)

What is e^{-ln(1-y)dy} ?
The solution to e^{-ln(1-y)dy} is 1/((-y+1)^{yd)}