What is (2x^2+1)^2(0.70711x)(4x) ?

The solution to (2x^2+1)^2(0.70711x)(4x) is 2.82844x^2(2x^2+1)^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (2x^2+1)^2(0.70711x)(4x)

simplify

(2 x^{2} + 1)^{2} (0.70711 x) (4 x)

2.82844 x^{2} (2 x^{2} + 1)^{2}

Solution steps

(2 x^{2} + 1)^{2} (0.70711 x) (4 x)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

xx = x^{1 + 1}

= (2 x^{2} + 1)^{2} \cdot 0.70711 \cdot 4 x^{1 + 1}

Add the numbers:

1 + 1 = 2

= (2 x^{2} + 1)^{2} \cdot 0.70711 \cdot 4 x^{2}

Multiply the numbers:

0.70711 \cdot 4 = 2.82844

= 2.82844 x^{2} (2 x^{2} + 1)^{2}

- 2 e^{- \frac{π}{4}}

4.02 \cdot 1 0^{- 9}

0.43 \cdot 1 0^{- 3}

(x - 2)^{3} (a + 2)^{3}

\frac{1}{2} e^{- 10 x}

What is (2x^2+1)^2(0.70711x)(4x) ?
The solution to (2x^2+1)^2(0.70711x)(4x) is 2.82844x^2(2x^2+1)^2