What is 2e^{-t}(1-e^{2t})^{-1} ?

The solution to 2e^{-t}(1-e^{2t})^{-1} is 2/(e^t(-e^{2t)+1)}

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simplify 2e^{-t}(1-e^{2t})^{-1}

simplify

2 e^{- t} (1 - e^{2 t})^{- 1}

\frac{2}{e ^{t} ( - e ^{2 t} + 1 )}

Solution steps

2 e^{- t} (1 - e^{2 t})^{- 1}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= 2 \cdot \frac{1}{e ^{t}} (- e^{2 t} + 1)^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= 2 \cdot \frac{1}{e ^{t}} \cdot \frac{1}{( - e ^{2 t} + 1 )}

Multiply fractions:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{1 \cdot 1 \cdot 2}{e ^{t} ( 1 - e ^{2 t} )}

Multiply the numbers:

1 \cdot 1 \cdot 2 = 2

= \frac{2}{e ^{t} ( - e ^{2 t} + 1 )}

85 e^{- 0.04 \cdot 10}

4.09 (10)^{- 3}

4.17 \cdot 1 0^{- 1}

(1.38 \cdot 1 0^{- 23}) (293) (6)

e^{- l n (5 x^{5})}

What is 2e^{-t}(1-e^{2t})^{-1} ?
The solution to 2e^{-t}(1-e^{2t})^{-1} is 2/(e^t(-e^{2t)+1)}