What is (\sqrt[8]{32})^2 ?

The solution to (\sqrt[8]{32})^2 is 2\sqrt[4]{2}

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simplify (\sqrt[8]{32})^2

simplify

Decimal Notation

2.37841 \dots

Solution steps

Apply radical rule:

= (3 2^{\frac{1}{8}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 3 2^{\frac{1}{8} \cdot 2}

\frac{1}{8} \cdot 2 = \frac{1}{4}

= 3 2^{\frac{1}{4}}

Prime factorization of

32 : 2^{5}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

Apply radical rule:

6.411 \cdot 1 0^{- 8} \cdot 2.35

100 e^{(- \frac{l n ( 2 )}{1590})}

e^{\frac{r t}{l}} (e^{- 0.1 t})

e^{c t} e^{- s t}

e^{3 x} e^{- 4}