What is u(t-a)e^{-bt}cos^2(t-a) ?

The solution to u(t-a)e^{-bt}cos^2(t-a) is (ucos^2(t-a)(t-a))/(e^{bt)}

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simplify u(t-a)e^{-bt}cos^2(t-a)

simplify

u (t - a) e^{- b t} cos^{2} (t - a)

\frac{u cos ^{2} ( t - a ) ( t - a )}{e ^{b t}}

Solution steps

u (t - a) e^{- b t} cos^{2} (t - a)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{b t}} u cos^{2} (t - a) (t - a)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot u ( t - a ) cos ^{2} ( t - a )}{e ^{b t}}

Multiply:

1 \cdot u = u

= \frac{u cos ^{2} ( t - a ) ( t - a )}{e ^{b t}}

\frac{7 x}{5}

(6.31 \cdot 1 0^{- 7}) (7.22)

(4500 k g) (9.8 m s^{2}) (30 m)

(4.68 \cdot 1 0^{- 23}) \cdot 8

(1.45)^{- 0, 7}

What is u(t-a)e^{-bt}cos^2(t-a) ?
The solution to u(t-a)e^{-bt}cos^2(t-a) is (ucos^2(t-a)(t-a))/(e^{bt)}