What is \sqrt[6]{(3x^2+2)^5} ?

The solution to \sqrt[6]{(3x^2+2)^5} is (3x^2+2)^{5/6}

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simplify \sqrt[6]{(3x^2+2)^5}

simplify

(3 x^{2} + 2)^{\frac{5}{6}}

Solution steps

Apply radical rule:

= ((3 x^{2} + 2)^{5})^{\frac{1}{6}}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

= (3 x^{2} + 2)^{5 \cdot \frac{1}{6}}

5 \cdot \frac{1}{6} = \frac{5}{6}

= (3 x^{2} + 2)^{\frac{5}{6}}

- 22 0.1

a^{2} \cdot q^{2}

2 x π x^{4} x^{8}

e^{- 3} \cdot 9

- 2 (0) e^{- (0)^{2}}

What is \sqrt[6]{(3x^2+2)^5} ?
The solution to \sqrt[6]{(3x^2+2)^5} is (3x^2+2)^{5/6}