What is 5*(1.602*10^{-19}) ?

The solution to 5*(1.602*10^{-19}) is (801)/(100*10^{19)}

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simplify 5(1.60210^{-19})

simplify

5 \cdot (1.602 \cdot 1 0^{- 19})

\frac{801}{100 \cdot 1 0 ^{19}}

Decimal Notation

8.01 E - 19

Solution steps

5 (1.602 \cdot 1 0^{- 19})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 19} = \frac{1}{1 0 ^{19}}

= 5 \cdot 1.602 \cdot \frac{1}{1 0 ^{19}}

1.602 \cdot \frac{1}{1 0 ^{19}} = \frac{801}{500 \cdot 1 0 ^{19}}

= 5 \cdot \frac{801}{500 \cdot 1 0 ^{19}}

5 \cdot \frac{801}{500 \cdot 1 0 ^{19}} = \frac{801}{100 \cdot 1 0 ^{19}}

= \frac{801}{100 \cdot 1 0 ^{19}}

t (100 t^{2})

(984.5 + 379.1) (2 - 5.5)^{- 2}

(9 + 3 x)^{- \frac{1}{2}}

211463700 (9 \cdot 1 0^{- 34})

7 \cdot 12.2

What is 5*(1.602*10^{-19}) ?
The solution to 5*(1.602*10^{-19}) is (801)/(100*10^{19)}