What are the solutions to the equation x^4-9x^2+8=0 ?

The solutions to the equation x^4-9x^2+8=0 are x=2sqrt(2),x=-2sqrt(2),x=1,x=-1

Find the zeros of x^4-9x^2+8=0

The zeros of x^4-9x^2+8=0 are x=2sqrt(2),x=-2sqrt(2),x=1,x=-1

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x^{4} - 9 x^{2} + 8 = 0

x = 22, x = - 22, x = 1, x = - 1

Solution steps

x^{4} - 9 x^{2} + 8 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} - 9 u + 8 = 0

Solve

u^{2} - 9 u + 8 = 0 : u = 8, u = 1

u = 8, u = 1

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 8 : x = 22, x = - 22

Solve

x^{2} = 1 : x = 1, x = - 1

The solutions are

x = 22, x = - 22, x = 1, x = - 1

9 x + 5 - 8 x + 14 = 20

\frac{18 x ^{3} y ^{3}}{12 x ^{4} y ^{7}}

12 5^{- \frac{2}{3}}

14 x - 6 < 24 - 4 x

30 a^{2} + 17 a - 21

What are the solutions to the equation x^4-9x^2+8=0 ?
The solutions to the equation x^4-9x^2+8=0 are x=2sqrt(2),x=-2sqrt(2),x=1,x=-1
Find the zeros of x^4-9x^2+8=0
The zeros of x^4-9x^2+8=0 are x=2sqrt(2),x=-2sqrt(2),x=1,x=-1