What is simplify-68e^{-2x}cos(4x)sin(4x) ?

The solution to simplify-68e^{-2x}cos(4x)sin(4x) is -(68cos(4x)sin(4x))/(e^{2x)}

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simplify-68e^{-2x}cos(4x)sin(4x)

simplify

- 68 e^{- 2 x} cos (4 x) sin (4 x)

- \frac{68 cos ( 4 x ) sin ( 4 x )}{e ^{2 x}}

Solution steps

- 68 e^{- 2 x} cos (4 x) sin (4 x)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= - 68 \cdot \frac{1}{e ^{2 x}} cos (4 x) sin (4 x)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{1 \cdot 68 cos ( 4 x ) sin ( 4 x )}{e ^{2 x}}

Multiply the numbers:

1 \cdot 68 = 68

= - \frac{68 cos ( 4 x ) sin ( 4 x )}{e ^{2 x}}

(9.2695 \cdot 1 0^{- 23}) \cdot 2

36.5 \cdot 1 0^{- 7}

36.5 \cdot 1 0^{- 6}

(2 d^{3}) (8 d^{2})

120 \cdot (1 + 1 \cdot 0.5)^{(- 1)}

What is simplify-68e^{-2x}cos(4x)sin(4x) ?
The solution to simplify-68e^{-2x}cos(4x)sin(4x) is -(68cos(4x)sin(4x))/(e^{2x)}