What are the solutions to the equation 4x^2+7=25 ?

The solutions to the equation 4x^2+7=25 are x= 3/(sqrt(2)),x=-3/(sqrt(2))

Find the zeros of 4x^2+7=25

The zeros of 4x^2+7=25 are x= 3/(sqrt(2)),x=-3/(sqrt(2))

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4 x^{2} + 7 = 25

x = \frac{3}{2}, x = - \frac{3}{2}

Decimal Notation

x = 2.12132 \dots, x = - 2.12132 \dots

Solution steps

4 x^{2} + 7 = 25

Move

7

to the right side

4 x^{2} = 18

Divide both sides by

4

x^{2} = \frac{9}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{9}{2}, x = - \frac{9}{2}

\frac{9}{2} = \frac{3}{2}

- \frac{9}{2} = - \frac{3}{2}

x = \frac{3}{2}, x = - \frac{3}{2}

\frac{6 ^{9}}{6 ^{7}}

- \frac{8}{3} - \frac{1}{2} b = - \frac{7}{2}

(\frac{π}{3})^{2}

\frac{x}{5} + 4 = 0

7 x^{2} - 30 x + 8

What are the solutions to the equation 4x^2+7=25 ?
The solutions to the equation 4x^2+7=25 are x= 3/(sqrt(2)),x=-3/(sqrt(2))
Find the zeros of 4x^2+7=25
The zeros of 4x^2+7=25 are x= 3/(sqrt(2)),x=-3/(sqrt(2))