What is 6.626*10^{-34}(320) ?

The solution to 6.626*10^{-34}(320) is (3313)/(25*2^{30)*5^{34}}

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simplify 6.626*10^{-34}(320)

simplify

6.626 \cdot 1 0^{- 34} (320)

\frac{3313}{25 \cdot 2 ^{30} \cdot 5 ^{34}}

Solution steps

6.626 \cdot 1 0^{- 34} (320)

Apply rule:

(a) = a

(320) = 320

= 6.626 \cdot 1 0^{- 34} \cdot 320

Multiply the numbers:

6.626 \cdot 320 = 2120.32

= 2120.32 \cdot 1 0^{- 34}

= 1 0^{- 34} \cdot 2120.32

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 34} = \frac{1}{1 0 ^{34}}

= \frac{1}{1 0 ^{34}} \cdot 2120.32

\frac{1}{1 0 ^{34}} \cdot 2120.32 = \frac{2120.32}{1 0 ^{34}}

= \frac{2120.32}{1 0 ^{34}}

\frac{2120.32}{1 0 ^{34}} = \frac{212032}{100 \cdot 1 0 ^{34}}

= \frac{212032}{100 \cdot 1 0 ^{34}}

Factor the number:

212032 = 4 \cdot 53008

= \frac{4 \cdot 53008}{100 \cdot 1 0 ^{34}}

Factor the number:

100 = 4 \cdot 25

= \frac{4 \cdot 53008}{4 \cdot 25 \cdot 1 0 ^{34}}

Cancel the common factor:

4

= \frac{53008}{25 \cdot 1 0 ^{34}}

Factor

53008 : 2^{4} \cdot 3313

= \frac{2 ^{4} \cdot 3313}{25 \cdot 1 0 ^{34}}

Factor

1 0^{34} : 2^{34} \cdot 5^{34}

= \frac{2 ^{4} \cdot 3313}{25 \cdot 2 ^{34} \cdot 5 ^{34}}

\frac{2 ^{4}}{2 ^{34}} = \frac{1}{2 ^{30}}

= \frac{3313}{25 \cdot 2 ^{30} \cdot 5 ^{34}}

0.03 e^{- \frac{7}{48} t}

(P n Q) u (P n Q^{C})

0.27 \cdot 1 0^{- 7}

\frac{x + 5}{x + 3}

(((- 3)^{2})^{- 5})^{3}

What is 6.626*10^{-34}(320) ?
The solution to 6.626*10^{-34}(320) is (3313)/(25*2^{30)*5^{34}}