What are the solutions to the equation 3=-x^2 ?

The solutions to the equation 3=-x^2 are x=sqrt(3)i,x=-sqrt(3)i

Find the zeros of 3=-x^2

The zeros of 3=-x^2 are x=sqrt(3)i,x=-sqrt(3)i

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3 = - x^{2}

x = 3 i, x = - 3 i

Solution steps

3 = - x^{2}

Switch sides

- x^{2} = 3

Divide both sides by

- 1

x^{2} = - 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 3, x = - - 3

- 3 = 3 i

- - 3 = - 3 i

x = 3 i, x = - 3 i

8 x - 15 = 3 x

(- \frac{4}{x})^{3}

3 x < 12

r^{2} = 78

2^{3}

What are the solutions to the equation 3=-x^2 ?
The solutions to the equation 3=-x^2 are x=sqrt(3)i,x=-sqrt(3)i
Find the zeros of 3=-x^2
The zeros of 3=-x^2 are x=sqrt(3)i,x=-sqrt(3)i