What is ((2048ln(2))/u)e^{-u} ?

The solution to ((2048ln(2))/u)e^{-u} is (2048ln(2))/(e^uu)

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simplify ((2048ln(2))/u)e^{-u}

simplify

(\frac{2048 ln ( 2 )}{u}) e^{- u}

\frac{2048 ln ( 2 )}{e ^{u} u}

Solution steps

(\frac{2048 ln ( 2 )}{u}) e^{- u}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{2048 ln ( 2 )}{u} \cdot \frac{1}{e ^{u}}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{2048 ln ( 2 ) \cdot 1}{u e ^{u}}

Multiply the numbers:

2048 \cdot 1 = 2048

= \frac{2048 ln ( 2 )}{e ^{u} u}

- 3 (1.6 \cdot 1 0^{- 19})

(2)

1 0^{70} e^{- 10}

150000 \cdot (1 + 0.03)^{- 5}

x e^{- x^{5}} (- 5)

What is ((2048ln(2))/u)e^{-u} ?
The solution to ((2048ln(2))/u)e^{-u} is (2048ln(2))/(e^uu)