What is \sqrt[3]{(7x^4+6x)^2} ?

The solution to \sqrt[3]{(7x^4+6x)^2} is (7x^4+6x)^{2/3}

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simplify \sqrt[3]{(7x^4+6x)^2}

simplify

(7 x^{4} + 6 x)^{\frac{2}{3}}

Solution steps

Apply radical rule:

= ((7 x^{4} + 6 x)^{2})^{\frac{1}{3}}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

= (7 x^{4} + 6 x)^{2 \cdot \frac{1}{3}}

2 \cdot \frac{1}{3} = \frac{2}{3}

= (7 x^{4} + 6 x)^{\frac{2}{3}}

0.5 (2)^{- 0.5}

e^{- 0.001 (1)}

- 7.911509816 (1 0^{- 3})

\frac{6}{41}

\frac{1}{8} e^{- \frac{1}{4}}

What is \sqrt[3]{(7x^4+6x)^2} ?
The solution to \sqrt[3]{(7x^4+6x)^2} is (7x^4+6x)^{2/3}